Can someone please help with this?
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Answer:
x= -2, x = 5
Step-by-step explanation:
[tex]\sqrt{5x+11}-1=x[/tex]
[tex]\sqrt{5x+11}=x+1[/tex]
[tex]5x+11=(x+1)^2[/tex]
[tex]5x+11=x^2 + 2x + 1[/tex]
[tex]0=x^2 + 2x + 1-5x-11[/tex]
[tex]0=x^2 -3x-10[/tex]
[tex]0=(x+2)(x-5)[/tex]
x= -2, x = 5
Answer:
Answer for x = 5
Step-by-step explanation:
√5x +11 - 1 = x We isolate
-√5x+11 = -x-1 We tidy up
√5x+11 = x+1 We raise both sides to second power
(√5x+11)2 = (x+1)2 After brackets we show after squaring
5x+11 = x2+2x+1 We rearrange the order
x2 - 3x -10 = 0 We count the roots = 2
{x1, x2}={5, -2} We show the roots and show original equation, where the root is isolated, after tidy up
√5x+11 = x+1 Plug in 5 for x as x =5
√5•(5)+11 = (5)+1 Then simplify
√36 = 6 Solution checks !!
Solution is:
x = 5
Original equation, root isolated, after tidy up
√5x+11 = x+1 Plug in -2 for x
√5•(-2)+11 = (-2)+1 Simplify
√1 = -1 Solution does not check
1 ≠ -1
Answer for x = 5