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Given the equation square root of quantity 3x minus 2 end quantity equals 4, solve for x and identify if it is an extraneous solution.

6; solution is extraneous
6; solution is not extraneous
two thirds; solution is extraneous
two thirds; solution is not extraneous

Respuesta :

6, solution is not extraneous.
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Answer:

6; solution is not extraneous

Step-by-step explanation:

[tex]\sqrt{3x-2} =4[/tex]

[tex](\sqrt{3x-2})^{2} = (4)^2[/tex]

[tex]3x-2= 16[/tex]

[tex]3x = 18[/tex]

[tex]x =6[/tex]

[tex]\sqrt{3(6)-2}=4[/tex]

[tex]\sqrt{18-2}=4[/tex]

[tex]\sqrt{16} =4[/tex]

[tex]4=4[/tex]

6; solution is not extraneous

because 4 is equal to 4, an extraneous answer would be the correct answer given, however when you plug it into the equation it is not equal

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