Solve for x. Then find the side lengths of the triangle. If needed, round to the nearest tenth of a foot
40 ft
3x ft
6x ft
x=____
side lengths =___ft
side lengths = ___ft

Solve for x Then find the side lengths of the triangle If needed round to the nearest tenth of a foot 40 ft 3x ft 6x ft x side lengths ft side lengths ft class=

Respuesta :

Given:

The given triangle is a right triangle.

The hypotenuse of the triangle is 40 feet.

The legs of the triangle are 3x feet and 6x feet.

We need to determine the value of x and the side lengths.

Value of x:

The value of x can be determined using the Pythagorean theorem.

Thus, we have;

  [tex]40^2=(3x)^2+(6x)^2[/tex]

[tex]1600=9x^2+36x^2[/tex]

[tex]1600=45x^2[/tex]

[tex]35.56=x^2[/tex]

 [tex]5.96=x[/tex]

Thus, the value of x is 5.96

Side lengths:

The side lengths can be determined by substituting the value of x.

Thus, we have;

Length 3x = [tex]3(5.96)=17.9 \ ft[/tex]

Length 6x = [tex]6(5.96)=35.8 \ ft[/tex]

Therefore, the side lengths are 17.9 feet and 35.8 feet.

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