Question

The slope of EF¯¯¯¯ is −5/2 .

Which segments are perpendicular to EF¯¯¯¯¯ ?

Select each correct answer.

LM¯¯¯¯¯¯ , where L is at (1, 9) and M is at (6, 11)
NP¯¯¯¯¯¯ , where N is at (−3, 4) and P is at (−8, 2)
GH¯¯¯¯¯¯ , where G is at (6, 7) and H is at (4, 12)
JK¯¯¯¯¯ , where J is at (3, −2) and K is at (5, −7)

Answer 1

Answer:

LM and NP

Step-by-step explanation:

LM= 2/5

NP=2/5

GH= -5/2

JK= =5/2

Answer 2

The line perpendicular to EF is LM and NP, the correct option is A and B.

What is Slope?

The slope is the measure of the steepness of a line and is determined for two points in a line by the formula

m = ( y₂ - y₁)/(x₂-x₁)

The line EF has a slope of -5/2

The product of the slopes of the line perpendicular to this line is -1

so the slope = 2/5

The line which has a slope of 2/5 will be perpendicular to line EF.

The slope of line LM is

m = ( 11-9)/(6-1) = 2/5

The slope of line NP

m = (2-4)/(-8+3) = 2/5

The slope of the line GH

m = (12-7)/(4-6) = -5/2

The slope of the line JK

m = (-7+2)/(5-3) = -5/2

Therefore, the line perpendicular to EF is LM and NP, the correct option is A and B.

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