Question

For the function f(1) = Pere, if P = 7 and r= 0.07, then what is the value of f(7)
to the nearest tenth?
O A. 11.4
O B. 9.4
O
c.0.1
O
D. 940.0
SUBMIT


Answer: 11.4

Answer 1

Answer:I think b

Step-by-step explanation:

Answer 2

Answer:

A. 11.4

Step-by-step explanation:

$f(t) = Pe^{rt}$

Data:

P = 7

r = 0.07

Calculation:

$\begin{array}{rcl}f(t) & = &Pe^{rt}\\f(7)& = & 7 e^{(0.07 \times 7)}\\ & = & 7 e^{0.49}\\& \approx & 7 \times 1.632\\ & \approx & \mathbf{11.4}\\\end{array}$