The Metabolic power,If we assume that lowering his body has no energetic cost is 667 J/min
The Metabolic power, If lowering of his body needs half of the energy is 1000J/min
Explanation:
1.If we assume that lowering his body has no energetic cost:
Metabolic energy in 5 minutes
= Increase in potential energy for 150 pushups
= (89 kg) × (25/100 m) × 150
= 3337.5 J
Metabolic power
= (3375.5 J) / (5 min)
= 667 J/min
The Metabolic power,If we assume that lowering his body has no energetic cost is 667 J/min
2.If lowering of his body needs half of the energy what it costs to raise it.
Metabolic power
= (667 J/min) × [1 + (1/2)]
= 1000 J/min
The Metabolic power, If lowering of his body needs half of the energy is 1000J/min