Respuesta :
1.596 grams is the mass of CuSO4 needed to prepare 100 ml solution of 0.1 M solution.
Explanation:
Data given:
Volume of the solution = 100 ml or 0.1 litre
molarity of the solution = 0.10 M
mass of CuS[tex]O_{4}[/tex] = ?
atomic mass of CuS[tex]O_{4}[/tex] = 159.6 grams/mole
The mass will calculated by using the following relations:
number of moles = [tex]\frac{mass}{atomic mass of 1 mole}[/tex] equation 1
molarity = [tex]\frac{number of moles}{volume}[/tex] equation 2
putting the value of number of moles in equation 2
molarity = [tex]\frac{mass}{atomic mass X Volume}[/tex]
mass = molarity x atomic mass x volume
mass = 0.1 x 0.1 x 159.6
= 1.596 grams
1.596 grams will form 100ml solution 0.1 M
1.596 grams of CuSO4 would be needed to prepare 100 mL of 0.10 M solution.
A 0.10 M solution of CuSO4 contains:
- 0.1 moles of solid CuSO4 in 1 liter of solution, or
- 0.01 moles in 100 mL of solution
Thus, 0.01 moles of CuSO4 would have an equivalent mass of:
mole = mass/molar mass
mass = mole x molar mass
= 0.01 x 159.6
= 1.596 grams
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