Respuesta :

The sum of the given series is 348950.

Step-by-step explanation:

Given,

The series is : -50+(-44)+(-38)+...+2038+2044

To find the sum of the series.

Formula

  • The sum of the nth order arithmetic series where a is the initial term and d is the common difference [tex]S_{n}[/tex] = [tex]\frac{n}{2}[/tex][2a+(n-1)d]
  • Last term [tex]a_{n}[/tex] = a+(n-1)d

Now,

Initial term (a) = -50

Common difference (d) = -44 - (-50) = -44+50 = 6

According to the problem,

-50+(n-1)6 = 2044

or, (n-1)6 = 2094

or, n-1 = 349

or, n = 350

Now,

The sum [tex]S_{n}[/tex] = [tex]\frac{350}{2}[/tex][2×(-50)+(350-1)×6]

= 348950

Hence,

The sum is 348950.