Question

In circle J with \text{m} \angle HLK= 30^{\circ}m∠HLK=30
∘
, find the angle measure of minor arc \stackrel{\Large \frown}{HK}.
HK
⌢
.

Answer 1

Answer:

The minor arc HK is 60 degrees

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The inscribed angle is half that of the arc it comprises.

so

$m\angle HLK=\frac{1}{2}(arc\ HK)$

we have

$m\angle HLK=30^o$

substitute the given value

$30^o=\frac{1}{2}(arc\ HK)$

$arc\ HK=60^o$

Remember that the measure of the minor arc must be less than 180 degrees

therefore

The minor arc HK is 60 degrees

Answer 2

Answer:

The minor arc HK is 60 degrees

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The inscribed angle is half that of the arc it comprises.

so

we have

substitute the given value

Remember that the measure of the minor arc must be less than 180 degrees

therefore

The minor arc HK is 60 degrees