It's a goofy question. These sides satisfy the triangle inequality, 7 < 4+5, so we can draw as many triangles as we care to with those sides.
The more interesting question is how many non-congruent triangles can we draw with those sides? The answer is only 1, because by SSS all triangles with those sides will be congruent.
If we're asking about how many triangles with these sides cannot be mapped to each other through translation and rotation, the answer is two, basically a pair of reflected copies.
So much for deconstructing this lousy question. Let's go with
Answer: 1
When two triangles are congruent, corresponding sides and angle both are equal.
Only one triangle can be drawn that fit the given description.
it is given that, A triangle has sides of length 7 cm, 4 cm, and 5 cm.
Two triangles that have corresponding congruent sides are congruent (SSS).
If triangle ABC has the sides AB=7 cm, AC=4 cm, BC=5 cm and the triangle MNP has MN=7 cm, MP=4 cm, and PN=5 cm then
[tex]AB=MN=7 cm\\\\AC=MP=4 cm\\\\BC=PN=5cm[/tex]
Hence, based on the axiom of congruent triangles side–side–side (SSS) triangle ABC is congruent with triangle MNP.
Learn more about the triangles here:
https://brainly.com/question/1058720?referrer=searchResults
