Question

(X-4) (x+2)=16
What’s the standard form

Answer 1

Step-by-step explanation:

$(x - 4)(x + 2) = 16 \\ {x}^{2} + (- 4 + 2)x + ( - 4) \times 2= 16 \\ {x}^{2} - 2x - 8 - 16 = 0 \\ {x}^{2} - 2x - 24 = 0 \\ is \: the \: standard \: form.$

Answer 2

Answer:

Step-by-step explanation:

(x-4)(x+2)=16

$x^{2}$+(-4+2)x+(-4)×2=16

$x^{2}$ - 2x - 8 - 16= 0

$x^{2}$ -2x -24 = 0