Answer:
B. The sum of the volume of X and Z equals the volume of Y.
Step-by-step explanation:
To solve the problem, we calculate the volume of the three solids, and then we compare them.
The volume of X is the volume of a hemisphere of radius r, which is half the volume of a sphere of radius r, so:
[tex]V_x = \frac{1}{2}(\frac{4}{3}\pi r^3)=\frac{2}{3}\pi r^3[/tex]
The volume of Y is the volume of a cylinder of radius r and height
h = r
so it is given by the formula:
[tex]V_Y=\pi r^2 h = \pi r^2 \cdot r = \pi r^3[/tex]
Finally, the volume of Z is the volume of a cone of radius r and height
h = r
So the volume is given by
[tex]V_Z = \frac{1}{3}\pi r^2 h = \frac{1}{3}\pi r^2 \cdot r = \frac{1}{3}\pi r^3[/tex]
So we see that the correct option is
B. The sum of the volume of X and Z equals the volume of Y.
In fact:
[tex]V_X + V_Z = \frac{2}{3}\pi r^3 + \frac{1}{3}\pi r^3 = \pi r^3 = V_Y[/tex]