Question

What volume of 12.0 M sulfuric acid is needed to prepare 300.0 mL of 2.50 M solution?

Answer 1

Answer:

n=c*V

=2.50*300x10^-3

=.75 moles of hcl

v=n/c

=.75/12

=.0625 L

convert to mL

=62.5mL