Question

What are the foci of the hyperbola whose equation is (x-6)^2/16-(y+7)^2/9= 1?

Answer 1

The foci of the hyperbola is (0,3) and (0,-3).

Step-by-step explanation:

Given,

The equation of the hyperbola: $\frac{(x-6)^{2} }{16} -\frac{(y+7)^{2} }{9} =1$

To find the foci of the given parabola

Formula

If the equation of the hyperbola:  $\frac{(x-h)^{2} }{a^{2} } -\frac{(y-k)^{2} }{b^{2} } =1$

The focus will be (0,±c) where c² = a²+b²

Now,

Here, a=3 and b=4

c² = 3²+4² = 25

or, c = ±5

Hence,

The foci of the hyperbola is (0,3) and (0,-3)

Answer 2

Answer:

(1, -7) and (11, -7)

or A on edge

Step-by-step explanation:

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