The oxidation state of O in H₃O⁺ is -2
From the question, the given ion is H3O+.
This can be written properly as H₃O⁺
To determine the oxidation state of O (that is Oxygen) in H₃O⁺,
The oxidation state of H (Hydrogen) here is +1
∴ We can form the equation
(+1 × 3) + O = +1
(NOTE: The expression is equated to +1 because the overall charge on the given ion is +1)
Then, we have
+3 + O = +1
Now, subtract 3 from both sides
+3 -3 + O = +1 -3
∴ O = -2
Hence, the oxidation state of O in H₃O⁺ is -2
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