Question

which is the value of this expression when m equals 3 and n equals -5


(6m with exponent of -1 x n with the exponent of 0) another exponent of -3

Answer 1

When you have a negative exponent, you move the base with the negative exponent to the other side of the fraction to make the exponent positive.

For example:

$\frac{1}{2y^{-3}} =\frac{y^3}{2}$    ("y" is the base with the negative exponent)

$x^{-5}$ or $\frac{x^{-5}}{1} =\frac{1}{x^5}$

When you multiply an exponent directly to a base with an exponent, you multiply the exponents together.

For example:

$(y^3)^2=y^{(3*2)}=y^6$

$(x^2)^4=x^{(2*4)}=x^8$

$(2n)^3$ or $(2^1n^1)^3=2^{(1*3)}n^{(1*3)}=2^3n^3=8n^3$

When you have an exponent of 0, the result will always equal 1

For example:

$x^0=1$

$5^0=1$

$y^0=1$

$(6m^{-1}*n^0)^{-3}$      I think you should first make the exponents positive

$\frac{1}{(\frac{6}{m^1} *n^0)^3}$    

Since you know:

m = 3

n = -5    Substitute/plug it into the equation

$\frac{1}{(\frac{6}{(3)^1}*(-5)^0)^3 }$

$\frac{1}{(2*1)^3}$

$\frac{1}{2^3}$

$\frac{1}{8}$