Answer:
[tex]\frac{ -b+/-\sqrt{b^2-4ac} }{2a}[/tex]
Step-by-step explanation:
1) the equation listed above is the quadratic formula! you can solve ANY quadratic equation with it
quadratic equations in the form of:
ax^2+bx+c
just substitute a,b,and c for the numbers in the quadratic equation!
2)factoring:
my 2nd favorite method:
your equation will be in the form of:
ax^2+bx+c
where you need to find:
what*what=c
and
what+what=b
once you find those two things out then substitute those numbers in place of "b"
for example:
x^2+7x+10
factors of 10: 5,2 10,1 -2,-5 -10,-1
factors of 10 that=7
5,2
so
x^2+5x+2x+10
now group this equation:
group a) x^2+5x
group b) 2x+10
gcf of group a) x
so
x(x+5)
group b) gcf:2
so
2(x+5)
combine the numbers outside the parantheses:
(x+2)(x+5)=0
x+2=0
x=-2
x+5=0
x=-5
hence x=-2,-5
hope this helps!
