Two concentric current loops lie in the same plane. The outer loop has twice the diameter of the inner loop. The inner loop carries a 1.0 A current in a clockwise direction. What current, and which direction, should the outer loop carry such that the magnetic field in the center of the loops is zero?

Respuesta :

Answer: The outer loop should carry a current of 2.0 A.

The current should flow in the counter-clockwise direction

Explanation: Please see the attachments below

Ver imagen Abdulazeez10
Ver imagen Abdulazeez10
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Using the relation for the the current in a magnetic loop, the current and direction in the inner loop would be 2.0 amperes in the clockwise direction

Using the relation for the magnetic field in a loop :

  • [tex] B =\frac{U_{0}I}{2R}[/tex]
  • R = Radius ; I = current
  • Inner loop Radius = [tex] R_{0} [/tex]

  • Outer loop Radius = [tex] R_{0} = 2R_{1} [/tex]

outer loop = Inner loop

[tex] \frac{I_{0}}{2 \times 2 R_{1}} = \frac{I_{1}}{2R_{1}}[/tex]

Current of inner loop = 1.0 ampere

[tex] \frac{I_{0}}{4R_{1}} = \frac{1}{2R_{1}}[/tex]

Cross multiply :

[tex] I_{0} \times 2R_{1} = 4R_{1}[/tex]

[tex] I_{0} = \frac{4R_{1}}{2R_{1}}[/tex]

[tex] I_{0} = 2[/tex]

Hence, the current of the inner loop is 2.0 ampere and it is in the clockwise direction.

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