Respuesta :
we know that
The equation of the line into point-slope form is equal to
[tex]y-y1=m(x-x1)[/tex]
where
m is the slope
(x1,y1) is the point
In this problem we have
[tex]y-4=\frac{1}{2}(x-1)[/tex]
therefore
The slope is equal to
[tex]m=\frac{1}{2}[/tex]
The point is equal to
[tex](1,4)[/tex]
Answer:
The slope of the line is [tex]\dfrac{1}{2}[/tex] and a point on the line is [tex](1, 4)[/tex]
Step-by-step explanation:
The general point slope of line passing through [tex](x_1,y_1)[/tex] and having slope as m.
[tex]y-y_1=m(x-x_1)[/tex]
The given equation of the straight line,
[tex]y-4=\dfrac{1}{2}(x-1)[/tex]
Comparing this to the general equation we get the point as [tex](1, 4)[/tex] and slope as [tex]\dfrac{1}{2}[/tex]
