Question

The sum of three numbers is 62. The second number is equal to the first number diminished by 4. The third number is four times the first. What are the number?
n; n-4; 4n
n; 4-n; n+4
n; n/4; n+4

Answer 1

x+y+z=62

second number (y) is equal to the first (x) diminished by 4 means
y=x-4

third (z) is 4 times the first (x) means
z=4x

sub 4x for z and x-4 for y
x+x-4+4x=62
add like terms
6x-4=62
add 4 to both sides
6x=66
divide both sides by 6
x=11
sub
y=x-4
y=11-4
y=7
z=4x
z=4(7)
z=28

the numbers are 11,7,28

the numbers are represented by n; n-4; 4n, first choice