Question

The length of a rectangle is 7 yd more than twice the width, and the area of the rectangle is 99 yds squared. Find the dimensions of the rectangle.

Answer 1

L is 7 more than twice W
L=7+2W

area ia 99
99=LW

sub 7+2W for L
99=(7+2W)W
99=7W+2W^2
minus 99 from both sides
0=2W^2+7W-99
factor
0=(W+9)(2W-11)
set each to zero

W+9=0
W=-9
fasle, measurement cannot be negative

2W-11=0
add 11
2W=11
divide 2
W=5.5

the width is 5.5
sub
L=7+2W
L=7+2(5.5)
L=7+11
L=18


the dimentions is 18yd by 5.5 yd