Question

Calculate the energy absorbed when 6.20 g of aluminum is heated from 10.0°C to 65.0°C if the specific
heat of aluminum is 0.900 J/g°C

Answer 1

Answer:

306.9

Explanation:

You should follow this formula q=mc ΔT

q= energy produced

X

m= mass of the product in grams

X

Δ= specific heat, the amount of heat it takes to raise the temp by 1 degree

X

final temp-initial temp/ temperature already given