Question

we started something new and I'm competely lost

Answer 1

Given:

Triangle ABC is similar to triangle XYZ.

The measures of the sides are AB = 6 cm, BC = 18 cm and XY = 12 cm

We need to determine the measure of side YZ.

Measure of YZ:

Since, ABC and XYZ are similar triangles, by using similar triangles property, we have;

$\frac{AB}{XY}=\frac{BC}{YZ}$

Let the length of YZ be x.

Substituting the values, we get;

$\frac{6}{12}=\frac{18}{x}$

Cross multiplying, we get;

$6x=12 \times 18$

$6x=216$

Dividing both sides by 6, we have;

$x=36$

Thus, the value of x is 36.

Hence, the measure of the side YZ is 36 cm.