Respuesta :
find the equations then set them equal to each other
y=a(x-h)^2+k
quadracit (h,k) is vertex
helicopeter
vertex at (16,20)
y=a(x-16)^2+20
a point is (4,25)
25=a(4-16)^2+20
25=a(-12)^2+20
25=a(144)+20
minus 20 both sides
5=a(144)
divide both sides by 155
5/144=a
y=(5/144)(x-16)^2+20
airplane
y=mx+b
m=slope
b=yint
slope=(y2-y1)/(x2-x1)
slope=(20-18)/(30-0)=2/30=1/15
y=1/15x+b
(0,18)
18=1/15(0)+b
18=b
y=1/15x+18
we have
y=(5/144)(x-16)^2+20
and
y=1/15x+18
set equal to each other and solve for x value
(5/144)(x-16)^2+20=1/15x+18
after some work
and disregard the negative value since that is not allowed
x=40.413
plug in
y=1/15(40.413)+18
y=20.6942
they cross at (40.413,20.6942)
y=a(x-h)^2+k
quadracit (h,k) is vertex
helicopeter
vertex at (16,20)
y=a(x-16)^2+20
a point is (4,25)
25=a(4-16)^2+20
25=a(-12)^2+20
25=a(144)+20
minus 20 both sides
5=a(144)
divide both sides by 155
5/144=a
y=(5/144)(x-16)^2+20
airplane
y=mx+b
m=slope
b=yint
slope=(y2-y1)/(x2-x1)
slope=(20-18)/(30-0)=2/30=1/15
y=1/15x+b
(0,18)
18=1/15(0)+b
18=b
y=1/15x+18
we have
y=(5/144)(x-16)^2+20
and
y=1/15x+18
set equal to each other and solve for x value
(5/144)(x-16)^2+20=1/15x+18
after some work
and disregard the negative value since that is not allowed
x=40.413
plug in
y=1/15(40.413)+18
y=20.6942
they cross at (40.413,20.6942)
Step-by-step explanation: y=1/15x+18 and y=5/144(x-16)2+20
Answer is A