Which expression is equivalent to (StartFraction (2 a Superscript negative 3 Baseline b Superscript 4 Baseline) squared Over (3 a Superscript 5 Baseline b) Superscript negative 2 Baseline EndFraction) Superscript negative 1?
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The expression equivalent to the given expression is [tex]\left[\dfrac{1}{(36a^{4}b^{10})}\right][/tex] and this can be determined by using the arithmetic operations.
Given :
Expression --- [tex]\left[\dfrac{(2a^{-3}b^4)^{2}}{(3a^5b)^{-2}}\right]^{-1}[/tex]
The following steps can be used in order to evaluate the given expression:
Step 1 - The arithmetic operations can be used in order to evaluate the given expression.
Step 2 - Write the given expression.
[tex]\left[\dfrac{(2a^{-3}b^4)^{2}}{(3a^5b)^{-2}}\right]^{-1}[/tex]
Step 3 - Simplify the above expression.
[tex]\left[\dfrac{1}{(3a^5b)^{2}(2a^{-3}b^4)^{2}}\right][/tex]
Step 4 - Open the brackets and square the given terms in the denominator.
[tex]\left[\dfrac{1}{(9a^{10}b^2)\times (4a^{-6}b^8)}\right][/tex]
Step 5 - Multiply the terms present in the denominator.
[tex]\left[\dfrac{1}{(36a^{4}b^{10})}\right][/tex]
Therefore, the correct option is C).
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