Respuesta :
The equation needed is: [tex]Q = m\cdot c_e\cdot \Delta T[/tex]
Using data of the problem:
[tex]Q = 10\ g\cdot 0.90\frac{J}{g\cdot ^\circ C}\cdot (55 - 22)^\circ C = \bf 297\ J[/tex]
Using data of the problem:
[tex]Q = 10\ g\cdot 0.90\frac{J}{g\cdot ^\circ C}\cdot (55 - 22)^\circ C = \bf 297\ J[/tex]
The heat are needed to raise the temperature of 10.0 g of aluminum from 22 degrees celcius to 55 degrees celcius, with the specific heat of aluminum equal to 0.90 joules, we apply mass times Cp times change in temp. The expression is 10 g * 0.90 J /g/C * (55-22) C equal to 297 Joules