The radius of a sphere is increasing at a constant of 2 cm/sec at the instant when the volume of the sphere is increasing at 32pi cm^3. sec, What is the surface area of the sphere?
The formula for the volume (v) of sphere is, v = 4πr³ / 3 The derivative is, dv/dt = 4πr²(dr/dt) It is given that the radius changes at a rate of 2 cm/sec which means that dr/dt is 2. dv/dt is also given to be 32π cm³/sec. Substituting these to the given, 32π = 4πr² x 2 The value of 4πr² which is the surface area is equal to 16π. Thus, the surface area of the sphere is 16π cm².
