Question

Find the zeros of the function f(x) = x2 +9x + 20 by factoring.

Answer 1

Let a and b be the factors of the expression such that x² + 9x + 20 = (x + a)(x + b). The sum of a and b is the numerical coefficient of the second term and their product is the constant.
                                 a + b = 9               ;  a = 9 - b
                                 ab = 20                 ; (9 - b)(b) = 20
The value of a and b are 4 and 5. The factors are therefore,
                                    (x + 4)(x + 5) 
To find the zero, equate the factors to zero which yields an answer equal to x = -4 and x = -5. 

Answer 2

The zero's of the functions are x =-4 and x = -5

Zero's of quadratic equation:

The zeros of a quadratic equation are the points where the graph of the quadratic equation crosses the x-axis.

we equate the given quadratic function to 0 and solve for the values of x that satisfy the quadratic equation.

Therefore, the zero's by factoring is as follows;

• f(x) = x² + 9x + 20

f(x) = x² + 9x + 20

f(x) = x² + 5x + 4x + 20

0 = (x+4)(x+5)

Therefore, the zeros are as follows:

• x + 4 = 0; x = -4
• x + 5 = 0; x = -5

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