An isosceles triangle has its vertex at the origin and its base parallel to the x-axis with the vertices above the axis on the curve y = 27-x^2. Find the largest area the triangle can have.
We are given with an isosceles triangle having a vertex on the curve given y =27-x^2 . The area of the triangle, A= xy = x (27-x^2) A' = 27-x^2-2x^2 = 0 x = 3 Amax = 3(27-9) = 54 units2
