Respuesta :
A particle is moving along a projectile path where the initial height is 96 feet with an initial speed of 16 feet per second.
let's find the maximum heightof the particle
s(t)=−16t2+16t+96
s(1/2)=−16(1/2)2+16(1/2)+96=−16(1/4)+8+96=−4+8+96=100
Therefore the answer is 100
let's find the maximum heightof the particle
s(t)=−16t2+16t+96
s(1/2)=−16(1/2)2+16(1/2)+96=−16(1/4)+8+96=−4+8+96=100
Therefore the answer is 100
The maximum height of this particle undergoing a projectile motion is equal to 100 feet.
Given the following data:
Initial height = 96 feet.
Initial speed = 16 feet per second.
How to calculate the maximum height of this particle?
First of all, we would determine the time at which the particle reaches a maximum height as follows:
t = u/2a
t = 16/2×16
t = 0.5 seconds.
Mathematically, the maximum height of this particle undergoing a projectile motion would be calculated by using this formula:
s(t) = -u₀t² + u₀t + h₀
s(0.5) = -16(0.5)² + 16(0.5) + 96
s(0.5) = -4 + 8 + 96
s(0.5) = 100 feet.
Read more on projectile motion here: https://brainly.com/question/24949996
#SPJ5