Question

Solve tan(x)(tan(x)-1) = 0

a. x = pi/3±2pi(n), x = 3pi/4±2pin.
b. x = pi/2±2pi(n), x = 3pi/2±2pi(n), x = ±2pi(n)
c. x = ±pi(n), x = pi/2±2pi(n)
d. x = ±n(pi), x = pi/4±n(pi)

Answer 1

$(\tan x)(\tan x-1)=0\\ \tan x= 0\\ x=n\pi,n\in\mathbb{Z}\\\\ \tan x -1=0\\ \tan x = 1\\ x=\dfrac{\pi}{4}+n\pi,n\in\mathbb{Z}$

D

Answer 2

In solving this question that you give you must first analyze every single detail of the equation, then look for the possible formulas and form a possible solution to the problems, next is to test if your solution is true and when its true is would be letter D. right? i hope you got the correct answer same as mine.