Question

It takes about 20 seconds for a jet plane to go from rest to the takeoff speed of 100 mph (44.7 m/s). What is the average horizontal force that the seat exerts on the back of a 96 kg passenger during takeoff?

Answer 1

Answer:

Correct answer:  F = 214.56 N

Explanation:

Given:

V₀ = 0 m/s   initial speed

V = 44.7 m/s  speed after t = 29 seconds

m = 96 kg

F = ?  horizontal force

Taking off an airplane is a uniformly accelerated motion to which the formula applies:

V = V₀ + a t   and  V₀ = 0 m/s

V = a t  ⇒ a = V / t = 44.7 / 20 = 2.235 m/s²

a = 2.235 m/s²

the horizontal force is calculated using the formula:

F = m · a = 96 · 2.235 = 214.56 N

F = 214.56 N

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