Respuesta :
False. You can pick any two numbers, but not the same number, to show its false. try it
Real number is the total of all numbers. The equation [tex]2a \cdot b = a^2 + b^2[/tex] is false.
Given
[tex]2a \cdot b = a^2 + b^2[/tex]
To prove or disprove the above equation, we simply assume values for a and b.
Assume that:
[tex]a=5[/tex]
[tex]b = 6.7[/tex]
The equation becomes:
[tex]2 \times 5 \times 6.7 = 5^2 + 6.7^2[/tex]
[tex]67 = 25 + 44.89[/tex]
[tex]67 = 68.89[/tex]
The above equation is false
i.e. [tex]67 \ne 68.89[/tex]
This means that: [tex]2a \cdot b = a^2 + b^2[/tex] is false
Read more about real numbers at:
https://brainly.com/question/1187875