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False. You can pick any two numbers, but not the same number, to show its false. try it

Real number is the total of all numbers. The equation [tex]2a \cdot b = a^2 + b^2[/tex] is false.

Given

[tex]2a \cdot b = a^2 + b^2[/tex]

To prove or disprove the above equation, we simply assume values for a and b.

Assume that:

[tex]a=5[/tex]

[tex]b = 6.7[/tex]

The equation becomes:

[tex]2 \times 5 \times 6.7 = 5^2 + 6.7^2[/tex]

[tex]67 = 25 + 44.89[/tex]

[tex]67 = 68.89[/tex]

The above equation is false

i.e. [tex]67 \ne 68.89[/tex]

This means that: [tex]2a \cdot b = a^2 + b^2[/tex] is false

Read more about real numbers at:

https://brainly.com/question/1187875

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