Question

What is the additive inverse of 16 5/7

Answer 1

The additive inverse of a number is what u add to that number to get 0.
The additive inverse of a = -a.....so the additive inverse of 16 5/7 = -16 5/7

Answer 2

Answer:

$-16\frac{5}{7}$

Step-by-step explanation:

we know that

Two numbers are additive inverse if their sum is equal to zero

Let

x-------> the additive inverse of $16\frac{5}{7}$

so

$x+16\frac{5}{7}=0$

solve for x

Subtract $16\frac{5}{7}$ both sides

$x+16\frac{5}{7}-16\frac{5}{7}=-16\frac{5}{7}$

$x=-16\frac{5}{7}$ -------> additive inverse