Question

which shows the correct substitution of the values a, b, and c from the equation 0 = 4x2 2x – 1 into the quadratic formula below? quadratic formula: x = -b±√b^2-4ac/2a

Answer 1

$0 = 4x^2+2x- 1$

Quadratic formula is

$x = \frac{-b+-\sqrt{b^2-4ac}}{2a}$

'a' is the coefficient of x^2 = 4

'b' is the coefficient of x = 2

'c' is the constant = -1

Now we plug in all the values in quadratic formula

$x = \frac{-b+-\sqrt{b^2-4ac}}{2a}$

$x = \frac{-2+-\sqrt{2^2-4(4)(-1)}}{2(4)}$

$x = \frac{-2+-\sqrt{18}}{8}$

The above one is the substitution of values of a,b,c in quadratic formula.

Answer 2

Answer:

Step-by-step explanation:

Its Option A for those who didn’t get the explanation.