Answer:
600 square centimeter.
Step-by-step explanation:
A cube-shaped satellite has side lengths of 10 centimeters.
So, the total surface area of the satellite is 2(10 × 10 + 10 × 10 + 10 × 10) = 600 sq. cm.
{The total surface area of a cuboid having length L, width W, and height H is given by 2(LW + WH + HL)}
Therefore, the least amount of aluminum needed to cover the satellite will be 600 sq. cm. (Answer)
