what mass (in g) of P2O5 would be produced if 0.590 moles of H2O are produced?
![what mass in g of P2O5 would be produced if 0590 moles of H2O are produced class=](https://us-static.z-dn.net/files/d7b/fac78bc1705b1bc8a348a8887b7e95d4.png)
Answer:
grams P₂O₅ produced = 27.9 grams
Explanation:
2H₃PO₄ => P₂O₅ + 3H₂O
for 0.590 mole yield of H₂O there will also be a yield of 1/3(0.590 mol P₂O₅) = 0.197 mol P₂O₅
gram mass yield of P₂O₅ = (0.197 mol P₂O₅)(142 g/mol) = 27.9 grams P₂O₅