What is the length of AB, to the nearest tenth of a centimeter?
10.5 cm
13.7 cm
15.7 cm
17.9 cm
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The length of side AB in the triangle is 13.7 cm.
Sine rule is used to show the relationship between the sides and angles of a triangle. It is given by:
a / sinA = b / sinB = c / sinC
Where a, b, c are the sides and A, B, C are the respective opposite angles.
From the diagram, using sine rule:
12/sin(42) = AB/sin(50)
AB = 13.7 cm
The length of side AB in the triangle is 13.7 cm.
Find out more on sine rule at: https://brainly.com/question/4372174