Respuesta :

Answer:

D

Step-by-step explanation:

you want to solve it out

start with multiplying z to each. you don't multiply it to the 6 because it is in the same parenthesis set, but you multiply it to everything in the other set.  After multiplying, you get: [tex]2z^3[/tex] , [tex]3z^{2}[/tex] , [tex]5z[/tex]

now do that to the 6. After multiplying you get:  [tex]12z^{2}[/tex], [tex]18z[/tex], [tex]30[/tex]

now set it all next to each other [tex]2z^3[/tex] + [tex]3z^{2}[/tex] + [tex]5z[/tex] + [tex]12z^{2}[/tex] + [tex]18z[/tex] + [tex]30[/tex]

now combine like terms. start with the to the highest power. since there is only one that has a third power, you put that one first. then you combine the squared ones, and so forth.

work combining the squares: [tex]3z^{2} + 12z^{2} = 15z^{2}[/tex]

work combing the single z's: [tex]5z + 18z = 23z[/tex]

to get this:  [tex]2z^3[/tex] + [tex]15z^{2}[/tex] + [tex]23z[/tex] + [tex]30[/tex]

so, the answer is D

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