Respuesta :
Answer:
The t value for 95% confidence with df = 9 is t = 2.262.
Step-by-step explanation:
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Answer:
The value of t-score for 95% confidence interval and a sample of size 5 is 2.776.
Step-by-step explanation:
The (1 - α)% confidence interval for population mean (μ) in case the population standard deviation is not known is given by:
[tex]CI=\bar x\pm t_{\alpha/2, (n-1)}\times \frac{s}{\sqrt{n}}[/tex]
Here,
[tex]\bar x[/tex] = sample mean
s = sample standard deviation
n = sample size
[tex]t_{\alpha/2, (n-1)}[/tex] = critical value.
The information provided is:
The confidence level is, (1 - α)% = 95%.
The sample size is, n = 5.
Compute the t score as follows:
[tex]t_{\alpha/2, (n-1)}=t_{0.0.5/2, (5-1)}=t_{0.025, 4}=2.776[/tex]
*Use a t-table for the critical value.
Thus, the value of t-score for 95% confidence interval and a sample of size 5 is 2.776.
