The vertex form of parabola is,
[tex]y=a(x-p)^2+q[/tex]
Where [tex](p,q)[/tex] is vertex point.
In this case our parabola is given by,
[tex]y=1(x-3)^2+0[/tex]
Hence the vertex is at [tex](3,0)[/tex].
Hope this helps.
