Question

where does g(x) = x^2 – 10x + 24 touch the x-axis

Answer 1

Answer:

It touches at (6, 0) and (4, 0)

Step-by-step explanation:

Step 1:  Factor out the expression

$g(x) = x^2-10x+24$

$g(x) = x^2 - 6x - 4x + 24$

$g(x) = (x - 6)(x - 4)$

Step 2:  Solve for x

$x - 6 + 6 = 0 + 6$

$x = 6$

$x - 4 + 4 = 0 + 4$

$x = 4$

Answer:  It touches at (6, 0) and (4, 0)