You have been assigned to design an open cylindrical storage tank 4 meters tall with a diameter of 8 meters to be made out of A-36 steel. The tank will hold a fluid with density of rho = 1.2 g/cm^3 (or 1200 kg/m^3 ). Using a safety factor of 4, what wall thickness is required?

Respuesta :

Answer:

The required wall thickness is [tex]1.506 \times 10^{-3}[/tex] m

Explanation:

Given:

Fluid density [tex]\rho = 1200[/tex] [tex]\frac{kg}{m^{3} }[/tex]

Diameter of tank [tex]d = 8[/tex] m

Length of tank [tex]l = 4[/tex] m

F.S = 4

For A-36 steel yield stress [tex]\sigma = 250[/tex] MPa,

Allowable stress [tex]\sigma _{allow} = \frac{\sigma}{F.S}[/tex]

 [tex]\sigma _{allow} = \frac{250}{4} = 62.5[/tex] MPa

Pressure force is given by,

 [tex]P = \rho gh[/tex]

 [tex]P = 1200 \times 9.8 \times 4[/tex]

[tex]P = 47088[/tex] Pa

Now for a vertical pipe,

[tex]\sigma _{allow} = \frac{Pd}{4t}[/tex]

Where [tex]t =[/tex] required thickness

 [tex]t = \frac{Pd}{4 \sigma _{allow} }[/tex]

 [tex]t = \frac{47088 \times 8 }{4 \times 62.5 \times 10^{6} }[/tex]

[tex]t = 1.506 \times 10^{-3}[/tex] m

Therefore, the required wall thickness is [tex]1.506 \times 10^{-3}[/tex] m

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