Answer:
The minimum distance moved by mirror is 125 nm
Explanation:
Given:
Wavelength of light [tex]\lambda = 500 \times 10^{-9}[/tex] m
Here given in question, spot of constructive interference change to a destructive interference.
Hence minimum distance moved by one of mirror is given by,
[tex]t = \frac{1}{2}(\frac{\lambda}{2} )[/tex]
Where [tex]t =[/tex] distance moved by mirror
[tex]t = \frac{\lambda }{4}[/tex]
[tex]t = \frac{500\times 10^{-9} }{4}[/tex]
[tex]t = 125 \times 10 ^{-9}[/tex]
Therefore, the minimum distance moved by mirror is 125 nm