Question

An Aiken High school track athlete is participating in the 100-meter hurdle event. If the
runner's initial vertical jump is 2.0 m/s, how much will the runner's center of mass be
raised during the jump?

Answer 1

Answer:

Center of mass of the athlete will reach to maximum height of 20 cm

Explanation:

Here we know that initial speed of the athlete in vertical direction is given as

$v_y = 2 m/s$

now we know that acceleration due to gravity will oppose its motion in opposite direction

so we have

$v_f^2 - v_i^2 = 2 a d$

so when it reach maximum height the final speed becomes zero

so we have

$0 - 2^2 = 2(9.81)H$

$H = 0.20 m$