Question

A ray in diamond (n = 2.42) has a critical angle of 41.7 deg when trying to enter benzene. What is the index of refraction in benzene?

Answer 1

Answer: 1.50

Explanation:

Given that:

C (critical angle) = 41.7°

n (index of refraction in benzene) = 2.42

n (index of refraction in benzene) = ?

To get the index of refraction in benzene, Apply the formula n = 1/sineC,

n = 1/sine41.7°

n = 1/sine 41.7°

n = (1/0.6652)

n = 1.50

Thus, the index of refraction for the ray in benzene is 1.50

Answer 2

Answer:

1.61 is the answer

Explanation:

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