Answer:
B. 54.0
Explanation:
An aqueous 0.300 M glucose solution is prepared with a total volume of 180.16 mol. Molecular Weight Of Glucose Is 180.16 Mol.
Mass Of Glucose = 54.0 Grams.
[tex]mass of glucose = \frac{0.3 mole}{litre} * \frac{180.16}{litre} = 54.0[/tex]