Answer:
Nothing
Explanation:
To solve this problem, we can use the Combined Gas Laws:
[tex]\dfrac{p_{1}V_{1} }{n_{1}T_{1}} = \dfrac{p_{2}V_{2} }{n_{2}T_{2}}[/tex]
Data:
p₁ = p₁; V₁ = V₁; n₁ = n₁; T₁ = T₁
p₂ = ?; V₂ = 2V₁; n₂ = 2n₁; T₂ = T₁
Calculation:
[tex]\begin{array}{rcl}\dfrac{p_{1}V_{1}}{n_{1}T_{1}} & = &\dfrac{p_{2}V_{2}}{n_{2}T_{2}}\\\\\dfrac{p_{1}V_{1}}{n _{1}T_{1}} & = &\dfrac{p_{2}\times 2V_{1}}{2n _{1}T_{1}}\\\\p_{1} & = &\dfrac{p_{2}\times 2}{2}\\\\p_{2} & = & \mathbf{p_{1}}\\\end{array}\\\text{The pressure does not change.}[/tex]