A gas sample is help at a constant temperature, Whay happens to the pressure of the sample if the volume is doubled and the number of molecules is doubled ?

Respuesta :

znk

Answer:

Nothing  

Explanation:

To solve this problem, we can use the Combined Gas Laws:

[tex]\dfrac{p_{1}V_{1} }{n_{1}T_{1}} = \dfrac{p_{2}V_{2} }{n_{2}T_{2}}[/tex]

Data:

p₁ = p₁; V₁ =   V₁; n₁ =      n₁; T₁  = T₁

p₂ = ?;   V₂ = 2V₁; n₂ = 2n₁; T₂ =  T₁

Calculation:

[tex]\begin{array}{rcl}\dfrac{p_{1}V_{1}}{n_{1}T_{1}} & = &\dfrac{p_{2}V_{2}}{n_{2}T_{2}}\\\\\dfrac{p_{1}V_{1}}{n _{1}T_{1}} & = &\dfrac{p_{2}\times 2V_{1}}{2n _{1}T_{1}}\\\\p_{1} & = &\dfrac{p_{2}\times 2}{2}\\\\p_{2} & = & \mathbf{p_{1}}\\\end{array}\\\text{The pressure does not change.}[/tex]

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