Question

A gas sample is help at a constant temperature, Whay happens to the pressure of the sample if the volume is doubled and the number of molecules is doubled ?

Answer 1

Answer:

Nothing  

Explanation:

To solve this problem, we can use the Combined Gas Laws:

$\dfrac{p_{1}V_{1} }{n_{1}T_{1}} = \dfrac{p_{2}V_{2} }{n_{2}T_{2}}$

Data:

p₁ = p₁; V₁ =   V₁; n₁ =      n₁; T₁  = T₁

p₂ = ?;   V₂ = 2V₁; n₂ = 2n₁; T₂ =  T₁

Calculation:

$\begin{array}{rcl}\dfrac{p_{1}V_{1}}{n_{1}T_{1}} & = &\dfrac{p_{2}V_{2}}{n_{2}T_{2}}\\\\\dfrac{p_{1}V_{1}}{n _{1}T_{1}} & = &\dfrac{p_{2}\times 2V_{1}}{2n _{1}T_{1}}\\\\p_{1} & = &\dfrac{p_{2}\times 2}{2}\\\\p_{2} & = & \mathbf{p_{1}}\\\end{array}\\\text{The pressure does not change.}$