Respuesta :
Answer:
Account B
Value=$21,589.66
Step-by-step explanation:
#We determine the compounded amount after 10 years for each account using the formula:
[tex]A=P(1+i_m)^n, i_m=(1+i/m)^m-1, m-compoundings \ per \ year[/tex]
#For account A:
Given principal is $16,000, i=3% and n=10, m=4:
[tex](1+i_m)=(1+i/m)^m\\\\=(1+0.03/4)^4=1.03034\\\\\therefore A=16000(1.03034)^{10}\\\\=21573.75[/tex]
#For account B:
Given principal is $16,000, i=3% and n=10, m=12:
[tex](1+i_m)=(1+i/m)^m\\\\=(1+0.03/12)^{12}=1.03042\\\\\therefore A=16000(1.03042)^{10}\\\\\\\\=21589.66[/tex]
We compare the amounts after 10 years and get the difference:
[tex]B>A\\\\B-A=21589.66-21573\\\\=\$15.91[/tex]
Hence, account B has the most value after 10 years and has a value of $21,589.66
The account that would be worth more in 10 years is Account B and it would have a value of $21,589.66.
The formula that can be used to determine the value of the accounts after 10 years is:
FV = P (1 + r)^nm
- FV = Future value
- P = Present value
- R = interest rate
- m = number of compounding
- N = number of years
Account A:
$16,000 x (1 + 3%/4)^(4 x 10)
$16,000 x (1.0075)^40 = $21,573.58
Account B:
$16,000 x (1 + 3%/12)^(12 x 10)
$16,000 x (1.0025)^120 = $21,589.66
To learn more about future value, please check: https://brainly.com/question/14640433