Respuesta :
Answer:
The potential wrt. calomel is 1.254 V
Explanation:
Given:
Potential wrt. silver chloride [tex]E_{Ag} = 1.201[/tex] V
Potential wrt. saturated silver chloride [tex]E = 0.197[/tex] V
Potential wrt. SCE [tex]E_{Hg} = 0.241[/tex] V
Now potential wrt. hydrogen is given by,
[tex]= 1.201- 0.197[/tex]
[tex]= 1.004[/tex] V
And we find for potential wrt. calomel,
[tex]=[/tex] potential wrt. hydrogen + potential wrt. SEC
[tex]= 1.004 +0.241[/tex]
[tex]= 1.254[/tex] V
Therefore, the potential wrt. calomel is 1.254 V
The electrode potential relative to a saturated calomel electrode (S.C.E.) has been 1.254 V.
The electrode potential of the silver chloride has been 1.201 V, the saturated silver-silver chloride potential has been 0.197 V.
The potential of the silver chloride electrode with respect to hydrogen can be given by:
Potential with respect to hydrogen = Silver chloride potential - saturated potential
Potential with respect to hydrogen = 1.201 - 0.197 V
Potential with respect to hydrogen = 1.004 V
The electrode potential relative to a saturated calomel electrode (S.C.E.) can be given by:
= Potential with respect to hydrogen + potential with respect to S.C.E.
= 1.004 V + 0.241 V
= 1.254 V,
The electrode potential relative to a saturated calomel electrode (S.C.E.) has been 1.254 V.
For more information about the electrode potential, refer to the link:
https://brainly.com/question/14306552